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120032013123203 = 238150412437263
BaseRepresentation
bin11011010010101100100001…
…100000001111111010000011
3120201222221121101010012012012
4123102230201200033322003
5111213101030324420303
61103141540125123135
734166012116222646
oct3322544140177203
9521887541105165
10120032013123203
11352783221a8525
12115670123b94ab
1351c8c7c8b241c
14218d81a9cba5d
15dd2494d855d8
hex6d2b2180fe83

120032013123203 has 4 divisors (see below), whose sum is σ = 120082425562848. Its totient is φ = 119981600683560.

The previous prime is 120032013123133. The next prime is 120032013123277. The reversal of 120032013123203 is 302321310230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120032013123203 - 220 = 120032012074627 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120032013123283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25206216251 + ... + 25206221012.

It is an arithmetic number, because the mean of its divisors is an integer number (30020606390712).

Almost surely, 2120032013123203 is an apocalyptic number.

120032013123203 is a deficient number, since it is larger than the sum of its proper divisors (50412439645).

120032013123203 is an equidigital number, since it uses as much as digits as its factorization.

120032013123203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50412439644.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 120032013123203 its reverse (302321310230021), we get a palindrome (422353323353224).

The spelling of 120032013123203 in words is "one hundred twenty trillion, thirty-two billion, thirteen million, one hundred twenty-three thousand, two hundred three".

Divisors: 1 2381 50412437263 120032013123203