Base | Representation |
---|---|
bin | 11011010010101100100001… |
… | …100000001111111010000011 |
3 | 120201222221121101010012012012 |
4 | 123102230201200033322003 |
5 | 111213101030324420303 |
6 | 1103141540125123135 |
7 | 34166012116222646 |
oct | 3322544140177203 |
9 | 521887541105165 |
10 | 120032013123203 |
11 | 352783221a8525 |
12 | 115670123b94ab |
13 | 51c8c7c8b241c |
14 | 218d81a9cba5d |
15 | dd2494d855d8 |
hex | 6d2b2180fe83 |
120032013123203 has 4 divisors (see below), whose sum is σ = 120082425562848. Its totient is φ = 119981600683560.
The previous prime is 120032013123133. The next prime is 120032013123277. The reversal of 120032013123203 is 302321310230021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120032013123203 - 220 = 120032012074627 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120032013123283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25206216251 + ... + 25206221012.
It is an arithmetic number, because the mean of its divisors is an integer number (30020606390712).
Almost surely, 2120032013123203 is an apocalyptic number.
120032013123203 is a deficient number, since it is larger than the sum of its proper divisors (50412439645).
120032013123203 is an equidigital number, since it uses as much as digits as its factorization.
120032013123203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50412439644.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 120032013123203 its reverse (302321310230021), we get a palindrome (422353323353224).
The spelling of 120032013123203 in words is "one hundred twenty trillion, thirty-two billion, thirteen million, one hundred twenty-three thousand, two hundred three".
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