12003233113 has 4 divisors (see below), whose sum is σ = 12004999168. Its totient is φ = 12001467060.

The previous prime is 12003233107. The next prime is 12003233117. The reversal of 12003233113 is 31133230021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12003233113 - 2⁹ = 12003232601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12003233117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 872793 + ... + 886438.

It is an arithmetic number, because the mean of its divisors is an integer number (3001249792).

Almost surely, 2^12003233113 is an apocalyptic number.

It is an amenable number.

12003233113 is a deficient number, since it is larger than the sum of its proper divisors (1766055).

12003233113 is an equidigital number, since it uses as much as digits as its factorization.

12003233113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1766054.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 12003233113 its reverse (31133230021), we get a palindrome (43136463134).

The spelling of 12003233113 in words is "twelve billion, three million, two hundred thirty-three thousand, one hundred thirteen".