1200343120003 has 4 divisors (see below), whose sum is σ = 1200406384840. Its totient is φ = 1200279855168.

The previous prime is 1200343119973. The next prime is 1200343120013. The reversal of 1200343120003 is 3000213430021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1200343120003 - 2⁵ = 1200343119971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200343120013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31603950 + ... + 31641907.

It is an arithmetic number, because the mean of its divisors is an integer number (300101596210).

Almost surely, 2^{1200343120003} is an apocalyptic number.

1200343120003 is a deficient number, since it is larger than the sum of its proper divisors (63264837).

1200343120003 is an equidigital number, since it uses as much as digits as its factorization.

1200343120003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63264836.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 1200343120003 its reverse (3000213430021), we get a palindrome (4200556550024).

The spelling of 1200343120003 in words is "one trillion, two hundred billion, three hundred forty-three million, one hundred twenty thousand, three".