120040110433 has 4 divisors (see below), whose sum is σ = 123284437780. Its totient is φ = 116795783088.

The previous prime is 120040110397. The next prime is 120040110461. The reversal of 120040110433 is 334011040021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334011040021 = 211 ⋅1582990711.

It can be written as a sum of positive squares in 2 ways, for example, as 55520554384 + 64519556049 = 235628^2 + 254007^2 .

It is a cyclic number.

It is not a de Polignac number, because 120040110433 - 2¹³ = 120040102241 is a prime.

It is a super-2 number, since 2×120040110433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 120040110433.

It is not an unprimeable number, because it can be changed into a prime (120040180433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1622163618 + ... + 1622163691.

It is an arithmetic number, because the mean of its divisors is an integer number (30821109445).

Almost surely, 2^120040110433 is an apocalyptic number.

It is an amenable number.

120040110433 is a deficient number, since it is larger than the sum of its proper divisors (3244327347).

120040110433 is an equidigital number, since it uses as much as digits as its factorization.

120040110433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3244327346.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 120040110433 its reverse (334011040021), we get a palindrome (454051150454).

The spelling of 120040110433 in words is "one hundred twenty billion, forty million, one hundred ten thousand, four hundred thirty-three".