Base | Representation |
---|---|
bin | 11011010011010011000111… |
… | …011011000111001000100001 |
3 | 120202010220120021201211210210 |
4 | 123103103013123013020201 |
5 | 111214240412041000230 |
6 | 1103212552045244333 |
7 | 34202010030504210 |
oct | 3323230733071041 |
9 | 522126507654723 |
10 | 120073451500065 |
11 | 35293957077378 |
12 | 11573057b636a9 |
13 | 51ccb5495c24b |
14 | 219182c21b077 |
15 | dd35bcc92eb0 |
hex | 6d34c76c7221 |
120073451500065 has 16 divisors (see below), whose sum is σ = 219562882743168. Its totient is φ = 54890720685696.
The previous prime is 120073451500049. The next prime is 120073451500103. The reversal of 120073451500065 is 560005154370021.
It is not a de Polignac number, because 120073451500065 - 24 = 120073451500049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120073451499996 and 120073451500032.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 571778340372 + ... + 571778340581.
It is an arithmetic number, because the mean of its divisors is an integer number (13722680171448).
Almost surely, 2120073451500065 is an apocalyptic number.
120073451500065 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
120073451500065 is a deficient number, since it is larger than the sum of its proper divisors (99489431243103).
120073451500065 is a wasteful number, since it uses less digits than its factorization.
120073451500065 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1143556680968.
The product of its (nonzero) digits is 126000, while the sum is 39.
The spelling of 120073451500065 in words is "one hundred twenty trillion, seventy-three billion, four hundred fifty-one million, five hundred thousand, sixty-five".
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