Search a number
-
+
12007576131 = 34002525377
BaseRepresentation
bin10110010111011010…
…10001001001000011
31010222211101001211220
423023231101021003
5144042414414011
65303300010123
7603362466405
oct131355211103
933884331756
1012007576131
115101a66741
1223b1390943
1311948b8045
1481ca30b75
154a426a506
hex2cbb51243

12007576131 has 4 divisors (see below), whose sum is σ = 16010101512. Its totient is φ = 8005050752.

The previous prime is 12007576079. The next prime is 12007576157. The reversal of 12007576131 is 13167570021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12007576131 - 27 = 12007576003 is a prime.

It is a super-2 number, since 2×120075761312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12007576092 and 12007576101.

It is not an unprimeable number, because it can be changed into a prime (12007576531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001262686 + ... + 2001262691.

It is an arithmetic number, because the mean of its divisors is an integer number (4002525378).

Almost surely, 212007576131 is an apocalyptic number.

12007576131 is a deficient number, since it is larger than the sum of its proper divisors (4002525381).

12007576131 is an equidigital number, since it uses as much as digits as its factorization.

12007576131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4002525380.

The product of its (nonzero) digits is 8820, while the sum is 33.

The spelling of 12007576131 in words is "twelve billion, seven million, five hundred seventy-six thousand, one hundred thirty-one".

Divisors: 1 3 4002525377 12007576131