12010303113 has 4 divisors (see below), whose sum is σ = 16013737488. Its totient is φ = 8006868740.

The previous prime is 12010303099. The next prime is 12010303141. The reversal of 12010303113 is 31130301021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12010303113 - 2¹³ = 12010294921 is a prime.

It is a super-2 number, since 2×12010303113² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12010303092 and 12010303101.

It is not an unprimeable number, because it can be changed into a prime (12010303913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001717183 + ... + 2001717188.

It is an arithmetic number, because the mean of its divisors is an integer number (4003434372).

Almost surely, 2^12010303113 is an apocalyptic number.

It is an amenable number.

12010303113 is a deficient number, since it is larger than the sum of its proper divisors (4003434375).

12010303113 is an equidigital number, since it uses as much as digits as its factorization.

12010303113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4003434374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 12010303113 its reverse (31130301021), we get a palindrome (43140604134).

The spelling of 12010303113 in words is "twelve billion, ten million, three hundred three thousand, one hundred thirteen".