1201034124131 has 4 divisors (see below), whose sum is σ = 1212694649712. Its totient is φ = 1189373598552.

The previous prime is 1201034123987. The next prime is 1201034124133. The reversal of 1201034124131 is 1314214301021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201034124131 - 2²⁶ = 1200967015267 is a prime.

It is a super-2 number, since 2×1201034124131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201034124097 and 1201034124106.

It is not an unprimeable number, because it can be changed into a prime (1201034124133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5830262636 + ... + 5830262841.

It is an arithmetic number, because the mean of its divisors is an integer number (303173662428).

Almost surely, 2^{1201034124131} is an apocalyptic number.

1201034124131 is a deficient number, since it is larger than the sum of its proper divisors (11660525581).

1201034124131 is a wasteful number, since it uses less digits than its factorization.

1201034124131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11660525580.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1201034124131 its reverse (1314214301021), we get a palindrome (2515248425152).

The spelling of 1201034124131 in words is "one trillion, two hundred one billion, thirty-four million, one hundred twenty-four thousand, one hundred thirty-one".