1201102020033 has 4 divisors (see below), whose sum is σ = 1601469360048. Its totient is φ = 800734680020.

The previous prime is 1201102019917. The next prime is 1201102020059. The reversal of 1201102020033 is 3300202011021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201102020033 - 2¹⁶ = 1201101954497 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201102019994 and 1201102020021.

It is not an unprimeable number, because it can be changed into a prime (1201102020133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200183670003 + ... + 200183670008.

It is an arithmetic number, because the mean of its divisors is an integer number (400367340012).

Almost surely, 2^{1201102020033} is an apocalyptic number.

It is an amenable number.

1201102020033 is a deficient number, since it is larger than the sum of its proper divisors (400367340015).

1201102020033 is an equidigital number, since it uses as much as digits as its factorization.

1201102020033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400367340014.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1201102020033 its reverse (3300202011021), we get a palindrome (4501304031054).

The spelling of 1201102020033 in words is "one trillion, two hundred one billion, one hundred two million, twenty thousand, thirty-three".