Base | Representation |
---|---|
bin | 10001011110100111111… |
… | …010011110100001100001 |
3 | 11020211021122000100222220 |
4 | 101132213322132201201 |
5 | 124134334412000113 |
6 | 2315441140021253 |
7 | 152530462022052 |
oct | 21364772364141 |
9 | 4224248010886 |
10 | 1201113000033 |
11 | 423430a80531 |
12 | 17494a391829 |
13 | 8935906a8cb |
14 | 421c428c729 |
15 | 2139c78d523 |
hex | 117a7e9e861 |
1201113000033 has 8 divisors (see below), whose sum is σ = 1601595264096. Its totient is φ = 800686368000.
The previous prime is 1201113000029. The next prime is 1201113000041. The reversal of 1201113000033 is 3300003111021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1201113000033 - 22 = 1201113000029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201112999976 and 1201113000021.
It is not an unprimeable number, because it can be changed into a prime (1201113000083) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13857603 + ... + 13944008.
It is an arithmetic number, because the mean of its divisors is an integer number (200199408012).
Almost surely, 21201113000033 is an apocalyptic number.
It is an amenable number.
1201113000033 is a deficient number, since it is larger than the sum of its proper divisors (400482264063).
1201113000033 is a wasteful number, since it uses less digits than its factorization.
1201113000033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27816015.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1201113000033 its reverse (3300003111021), we get a palindrome (4501116111054).
The spelling of 1201113000033 in words is "one trillion, two hundred one billion, one hundred thirteen million, thirty-three", and thus it is an aban number.
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