120111330440001 has 4 divisors (see below), whose sum is σ = 160148440586672. Its totient is φ = 80074220293332.

The previous prime is 120111330439999. The next prime is 120111330440009. The reversal of 120111330440001 is 100044033111021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 120111330440001 - 2¹ = 120111330439999 is a prime.

It is a super-2 number, since 2×120111330440001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 120111330440001.

It is not an unprimeable number, because it can be changed into a prime (120111330440009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20018555073331 + ... + 20018555073336.

It is an arithmetic number, because the mean of its divisors is an integer number (40037110146668).

Almost surely, 2^{120111330440001} is an apocalyptic number.

It is an amenable number.

120111330440001 is a deficient number, since it is larger than the sum of its proper divisors (40037110146671).

120111330440001 is an equidigital number, since it uses as much as digits as its factorization.

120111330440001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40037110146670.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 120111330440001 its reverse (100044033111021), we get a palindrome (220155363551022).

The spelling of 120111330440001 in words is "one hundred twenty trillion, one hundred eleven billion, three hundred thirty million, four hundred forty thousand, one".