12011145524113 has 4 divisors (see below), whose sum is σ = 12012749798400. Its totient is φ = 12009541249828.

The previous prime is 12011145524093. The next prime is 12011145524129. The reversal of 12011145524113 is 31142554111021.

12011145524113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12011145524113 - 2¹⁷ = 12011145393041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12011145524513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 802125913 + ... + 802140886.

It is an arithmetic number, because the mean of its divisors is an integer number (3003187449600).

Almost surely, 2^{12011145524113} is an apocalyptic number.

It is an amenable number.

12011145524113 is a deficient number, since it is larger than the sum of its proper divisors (1604274287).

12011145524113 is an equidigital number, since it uses as much as digits as its factorization.

12011145524113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1604274286.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 12011145524113 its reverse (31142554111021), we get a palindrome (43153699635134).

The spelling of 12011145524113 in words is "twelve trillion, eleven billion, one hundred forty-five million, five hundred twenty-four thousand, one hundred thirteen".