12011313200323 has 4 divisors (see below), whose sum is σ = 12049203778560. Its totient is φ = 11973422622088.

The previous prime is 12011313200317. The next prime is 12011313200339. The reversal of 12011313200323 is 32300231311021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12011313200323 - 2²⁹ = 12010776329411 is a prime.

It is a super-3 number, since 3×12011313200323³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12011313200294 and 12011313200303.

It is not an unprimeable number, because it can be changed into a prime (12011313200363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18945288643 + ... + 18945289276.

It is an arithmetic number, because the mean of its divisors is an integer number (3012300944640).

Almost surely, 2^{12011313200323} is an apocalyptic number.

12011313200323 is a deficient number, since it is larger than the sum of its proper divisors (37890578237).

12011313200323 is an equidigital number, since it uses as much as digits as its factorization.

12011313200323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37890578236.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 12011313200323 its reverse (32300231311021), we get a palindrome (44311544511344).

The spelling of 12011313200323 in words is "twelve trillion, eleven billion, three hundred thirteen million, two hundred thousand, three hundred twenty-three".