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1201211012033 = 1235279724279
BaseRepresentation
bin10001011110101101110…
…000010111001111000001
311020211112110102220011222
4101132231300113033001
5124140040004341113
62315455000444425
7152533062064244
oct21365560271701
94224473386158
101201211012033
1142348133438a
12174977179715
1389373466586
14421d32c325b
15213a619de08
hex117adc173c1

1201211012033 has 4 divisors (see below), whose sum is σ = 1201220859840. Its totient is φ = 1201201164228.

The previous prime is 1201211012017. The next prime is 1201211012081. The reversal of 1201211012033 is 3302101121021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201211012033 - 24 = 1201211012017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201211012233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4738613 + ... + 4985666.

It is an arithmetic number, because the mean of its divisors is an integer number (300305214960).

Almost surely, 21201211012033 is an apocalyptic number.

It is an amenable number.

1201211012033 is a deficient number, since it is larger than the sum of its proper divisors (9847807).

1201211012033 is an equidigital number, since it uses as much as digits as its factorization.

1201211012033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9847806.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1201211012033 its reverse (3302101121021), we get a palindrome (4503312133054).

The spelling of 1201211012033 in words is "one trillion, two hundred one billion, two hundred eleven million, twelve thousand, thirty-three".

Divisors: 1 123527 9724279 1201211012033