Search a number
-
+
120122120113 = 335107358459
BaseRepresentation
bin110111111011111010…
…1100001011110110001
3102111001111221221210121
41233313311201132301
53432002230320423
6131103333530241
711451511113502
oct1576765413661
9374044857717
10120122120113
1146a41894836
121b3447a3981
13b4345a42a8
145b57654ba9
1531d0a7945d
hex1bf7d617b1

120122120113 has 4 divisors (see below), whose sum is σ = 120122813680. Its totient is φ = 120121426548.

The previous prime is 120122120089. The next prime is 120122120149. The reversal of 120122120113 is 311021221021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 120122120113 - 233 = 111532185521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120122120213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155878 + ... + 514336.

It is an arithmetic number, because the mean of its divisors is an integer number (30030703420).

Almost surely, 2120122120113 is an apocalyptic number.

It is an amenable number.

120122120113 is a deficient number, since it is larger than the sum of its proper divisors (693567).

120122120113 is an equidigital number, since it uses as much as digits as its factorization.

120122120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 693566.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 120122120113 its reverse (311021221021), we get a palindrome (431143341134).

The spelling of 120122120113 in words is "one hundred twenty billion, one hundred twenty-two million, one hundred twenty thousand, one hundred thirteen".

Divisors: 1 335107 358459 120122120113