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1201300113 = 313214114387
BaseRepresentation
bin100011110011010…
…0110001010010001
310002201110100221210
41013212212022101
54430013100423
6315112010333
741524611456
oct10746461221
93081410853
101201300113
11567114612
122963909a9
13161b5b190
14b578b82d
15706e5b93
hex479a6291

1201300113 has 16 divisors (see below), whose sum is σ = 1725869376. Its totient is φ = 738864960.

The previous prime is 1201300091. The next prime is 1201300153. The reversal of 1201300113 is 3110031021.

It is not a de Polignac number, because 1201300113 - 29 = 1201299601 is a prime.

It is a super-2 number, since 2×12013001132 = 2886243922987625538, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1201300153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76306 + ... + 90692.

It is an arithmetic number, because the mean of its divisors is an integer number (107866836).

Almost surely, 21201300113 is an apocalyptic number.

1201300113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1201300113 is a deficient number, since it is larger than the sum of its proper divisors (524569263).

1201300113 is a wasteful number, since it uses less digits than its factorization.

1201300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16544.

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 1201300113 is about 34659.7765861236. The cubic root of 1201300113 is about 1063.0422018422.

Adding to 1201300113 its reverse (3110031021), we get a palindrome (4311331134).

The spelling of 1201300113 in words is "one billion, two hundred one million, three hundred thousand, one hundred thirteen".

Divisors: 1 3 13 39 2141 6423 14387 27833 43161 83499 187031 561093 30802567 92407701 400433371 1201300113