1201300300113 has 8 divisors (see below), whose sum is σ = 1671374330688. Its totient is φ = 766046568144.

The previous prime is 1201300300099. The next prime is 1201300300121. The reversal of 1201300300113 is 3110030031021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1201300300113 - 2¹² = 1201300296017 is a prime.

It is a super-2 number, since 2×1201300300113² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1201300300092 and 1201300300101.

It is not an unprimeable number, because it can be changed into a prime (1201300308113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8705074570 + ... + 8705074707.

It is an arithmetic number, because the mean of its divisors is an integer number (208921791336).

Almost surely, 2^{1201300300113} is an apocalyptic number.

It is an amenable number.

1201300300113 is a deficient number, since it is larger than the sum of its proper divisors (470074030575).

1201300300113 is a wasteful number, since it uses less digits than its factorization.

1201300300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17410149303.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1201300300113 its reverse (3110030031021), we get a palindrome (4311330331134).

The spelling of 1201300300113 in words is "one trillion, two hundred one billion, three hundred million, three hundred thousand, one hundred thirteen".