1201301330131 has 8 divisors (see below), whose sum is σ = 1374955805024. Its totient is φ = 1028156855040.

The previous prime is 1201301330123. The next prime is 1201301330137. The reversal of 1201301330131 is 1310331031021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1201301330131 - 2³ = 1201301330123 is a prime.

It is a super-3 number, since 3×1201301330131³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201301330099 and 1201301330108.

It is not an unprimeable number, because it can be changed into a prime (1201301330137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 127494900 + ... + 127504321.

It is an arithmetic number, because the mean of its divisors is an integer number (171869475628).

Almost surely, 2^{1201301330131} is an apocalyptic number.

1201301330131 is a deficient number, since it is larger than the sum of its proper divisors (173654474893).

1201301330131 is an equidigital number, since it uses as much as digits as its factorization.

1201301330131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254999901.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1201301330131 its reverse (1310331031021), we get a palindrome (2511632361152).

The spelling of 1201301330131 in words is "one trillion, two hundred one billion, three hundred one million, three hundred thirty thousand, one hundred thirty-one".