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12013080335755 = 523229456164053
BaseRepresentation
bin1010111011010000001101…
…1000101101010110001011
31120112102212020001000012021
42232310003120231112023
53033310242031221010
641314422151025311
72346626221022122
oct256640330552613
946472766030167
1012013080335755
11391179a73a744
12142027036b237
13691aa060b725
142d7616c9aab9
1515c74b4408da
hexaed0362d58b

12013080335755 has 16 divisors (see below), whose sum is σ = 15108153468480. Its totient is φ = 9152475539328.

The previous prime is 12013080335747. The next prime is 12013080335777. The reversal of 12013080335755 is 55753308031021.

12013080335755 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 12013080335755 - 23 = 12013080335747 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 228055692 + ... + 228108361.

It is an arithmetic number, because the mean of its divisors is an integer number (944259591780).

Almost surely, 212013080335755 is an apocalyptic number.

12013080335755 is a deficient number, since it is larger than the sum of its proper divisors (3095073132725).

12013080335755 is a wasteful number, since it uses less digits than its factorization.

12013080335755 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 456164310.

The product of its (nonzero) digits is 378000, while the sum is 43.

Adding to 12013080335755 its reverse (55753308031021), we get a palindrome (67766388366776).

The spelling of 12013080335755 in words is "twelve trillion, thirteen billion, eighty million, three hundred thirty-five thousand, seven hundred fifty-five".

Divisors: 1 5 23 115 229 1145 5267 26335 456164053 2280820265 10491773219 52458866095 104461568137 522307840685 2402616067151 12013080335755