Base | Representation |
---|---|
bin | 1010111011010000001101… |
… | …1000101101010110001011 |
3 | 1120112102212020001000012021 |
4 | 2232310003120231112023 |
5 | 3033310242031221010 |
6 | 41314422151025311 |
7 | 2346626221022122 |
oct | 256640330552613 |
9 | 46472766030167 |
10 | 12013080335755 |
11 | 391179a73a744 |
12 | 142027036b237 |
13 | 691aa060b725 |
14 | 2d7616c9aab9 |
15 | 15c74b4408da |
hex | aed0362d58b |
12013080335755 has 16 divisors (see below), whose sum is σ = 15108153468480. Its totient is φ = 9152475539328.
The previous prime is 12013080335747. The next prime is 12013080335777. The reversal of 12013080335755 is 55753308031021.
12013080335755 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 12013080335755 - 23 = 12013080335747 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 228055692 + ... + 228108361.
It is an arithmetic number, because the mean of its divisors is an integer number (944259591780).
Almost surely, 212013080335755 is an apocalyptic number.
12013080335755 is a deficient number, since it is larger than the sum of its proper divisors (3095073132725).
12013080335755 is a wasteful number, since it uses less digits than its factorization.
12013080335755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 456164310.
The product of its (nonzero) digits is 378000, while the sum is 43.
Adding to 12013080335755 its reverse (55753308031021), we get a palindrome (67766388366776).
The spelling of 12013080335755 in words is "twelve trillion, thirteen billion, eighty million, three hundred thirty-five thousand, seven hundred fifty-five".
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