Base | Representation |
---|---|
bin | 1010111011010000010011… |
… | …0011011001101000100001 |
3 | 1120112102220212202212111001 |
4 | 2232310010303121220201 |
5 | 3033310314123010423 |
6 | 41314424400352001 |
7 | 2346626630061121 |
oct | 256640463315041 |
9 | 46472825685431 |
10 | 12013104110113 |
11 | 39118020a8777 |
12 | 1420278315601 |
13 | 691aa5513ab2 |
14 | 2d761a0c8c81 |
15 | 15c74d589cad |
hex | aed04cd9a21 |
12013104110113 has 8 divisors (see below), whose sum is σ = 12400864058880. Its totient is φ = 11625359190240.
The previous prime is 12013104110101. The next prime is 12013104110129. The reversal of 12013104110113 is 31101140131021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013104110113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013104110713) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2121445 + ... + 5341042.
It is an arithmetic number, because the mean of its divisors is an integer number (1550108007360).
Almost surely, 212013104110113 is an apocalyptic number.
It is an amenable number.
12013104110113 is a deficient number, since it is larger than the sum of its proper divisors (387759948767).
12013104110113 is an equidigital number, since it uses as much as digits as its factorization.
12013104110113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7514447.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 12013104110113 its reverse (31101140131021), we get a palindrome (43114244241134).
The spelling of 12013104110113 in words is "twelve trillion, thirteen billion, one hundred four million, one hundred ten thousand, one hundred thirteen".
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