Search a number
-
+
12013104110113 = 31519297462487
BaseRepresentation
bin1010111011010000010011…
…0011011001101000100001
31120112102220212202212111001
42232310010303121220201
53033310314123010423
641314424400352001
72346626630061121
oct256640463315041
946472825685431
1012013104110113
1139118020a8777
121420278315601
13691aa5513ab2
142d761a0c8c81
1515c74d589cad
hexaed04cd9a21

12013104110113 has 8 divisors (see below), whose sum is σ = 12400864058880. Its totient is φ = 11625359190240.

The previous prime is 12013104110101. The next prime is 12013104110129. The reversal of 12013104110113 is 31101140131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12013104110113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013104110713) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2121445 + ... + 5341042.

It is an arithmetic number, because the mean of its divisors is an integer number (1550108007360).

Almost surely, 212013104110113 is an apocalyptic number.

It is an amenable number.

12013104110113 is a deficient number, since it is larger than the sum of its proper divisors (387759948767).

12013104110113 is an equidigital number, since it uses as much as digits as its factorization.

12013104110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7514447.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 12013104110113 its reverse (31101140131021), we get a palindrome (43114244241134).

The spelling of 12013104110113 in words is "twelve trillion, thirteen billion, one hundred four million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 31 51929 1609799 7462487 231337097 387519487423 12013104110113