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12013111131 = 37572052911
BaseRepresentation
bin10110011000000100…
…11000011101011011
31011000012210021102220
423030002120131123
5144100324024011
65304014355123
7603460521420
oct131402303533
934005707386
1012013111131
1151050a721a
1223b31bbaa3
131195aa54a8
1481d671d47
154a49b0506
hex2cc09875b

12013111131 has 8 divisors (see below), whose sum is σ = 18305693184. Its totient is φ = 6864634920.

The previous prime is 12013111109. The next prime is 12013111181. The reversal of 12013111131 is 13111131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12013111131 - 211 = 12013109083 is a prime.

It is a super-2 number, since 2×120131111312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12013111131.

It is not an unprimeable number, because it can be changed into a prime (12013111181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 286026435 + ... + 286026476.

It is an arithmetic number, because the mean of its divisors is an integer number (2288211648).

Almost surely, 212013111131 is an apocalyptic number.

12013111131 is a deficient number, since it is larger than the sum of its proper divisors (6292582053).

12013111131 is an equidigital number, since it uses as much as digits as its factorization.

12013111131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 572052921.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 12013111131 its reverse (13111131021), we get a palindrome (25124242152).

The spelling of 12013111131 in words is "twelve billion, thirteen million, one hundred eleven thousand, one hundred thirty-one".

Divisors: 1 3 7 21 572052911 1716158733 4004370377 12013111131