120131212220203 has 4 divisors (see below), whose sum is σ = 120132147083760. Its totient is φ = 120130277356648.

The previous prime is 120131212220197. The next prime is 120131212220221. The reversal of 120131212220203 is 302022212131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120131212220203 is a prime.

It is a super-2 number, since 2×120131212220203² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120131612220203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 467239000 + ... + 467496037.

It is an arithmetic number, because the mean of its divisors is an integer number (30033036770940).

Almost surely, 2^{120131212220203} is an apocalyptic number.

120131212220203 is a deficient number, since it is larger than the sum of its proper divisors (934863557).

120131212220203 is an equidigital number, since it uses as much as digits as its factorization.

120131212220203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 934863556.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 120131212220203 its reverse (302022212131021), we get a palindrome (422153424351224).

The spelling of 120131212220203 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred twelve million, two hundred twenty thousand, two hundred three".