120131334404043 has 4 divisors (see below), whose sum is σ = 160175112538728. Its totient is φ = 80087556269360.

The previous prime is 120131334404027. The next prime is 120131334404051. The reversal of 120131334404043 is 340404433131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120131334404043 - 2⁴ = 120131334404027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120131334403995 and 120131334404013.

It is not an unprimeable number, because it can be changed into a prime (120131334804043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20021889067338 + ... + 20021889067343.

It is an arithmetic number, because the mean of its divisors is an integer number (40043778134682).

Almost surely, 2^{120131334404043} is an apocalyptic number.

120131334404043 is a deficient number, since it is larger than the sum of its proper divisors (40043778134685).

120131334404043 is an equidigital number, since it uses as much as digits as its factorization.

120131334404043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40043778134684.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 120131334404043 its reverse (340404433131021), we get a palindrome (460535767535064).

The spelling of 120131334404043 in words is "one hundred twenty trillion, one hundred thirty-one billion, three hundred thirty-four million, four hundred four thousand, forty-three".