12013200121321 has 4 divisors (see below), whose sum is σ = 13729371567232. Its totient is φ = 10297028675412.

The previous prime is 12013200121309. The next prime is 12013200121331. The reversal of 12013200121321 is 12312100231021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013200121321 - 2¹⁹ = 12013199597033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013200121331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 858085722945 + ... + 858085722958.

It is an arithmetic number, because the mean of its divisors is an integer number (3432342891808).

Almost surely, 2^{12013200121321} is an apocalyptic number.

It is an amenable number.

12013200121321 is a deficient number, since it is larger than the sum of its proper divisors (1716171445911).

12013200121321 is an equidigital number, since it uses as much as digits as its factorization.

12013200121321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1716171445910.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12013200121321 its reverse (12312100231021), we get a palindrome (24325300352342).

The spelling of 12013200121321 in words is "twelve trillion, thirteen billion, two hundred million, one hundred twenty-one thousand, three hundred twenty-one".