120132003202201 has 4 divisors (see below), whose sum is σ = 120132756866304. Its totient is φ = 120131249538100.

The previous prime is 120132003202193. The next prime is 120132003202223. The reversal of 120132003202201 is 102202300231021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120132003202201 - 2³ = 120132003202193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120132003202501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376592905 + ... + 376911766.

It is an arithmetic number, because the mean of its divisors is an integer number (30033189216576).

Almost surely, 2^{120132003202201} is an apocalyptic number.

It is an amenable number.

120132003202201 is a deficient number, since it is larger than the sum of its proper divisors (753664103).

120132003202201 is an equidigital number, since it uses as much as digits as its factorization.

120132003202201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 753664102.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 120132003202201 its reverse (102202300231021), we get a palindrome (222334303433222).

The spelling of 120132003202201 in words is "one hundred twenty trillion, one hundred thirty-two billion, three million, two hundred two thousand, two hundred one".