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120132020131 = 891349797979
BaseRepresentation
bin110111111100001101…
…1010010011110100011
3102111002012120221001221
41233320123102132203
53432012244121011
6131104330035511
711451661215514
oct1577033223643
9374065527057
10120132020131
1146a47436872
121b347b78b97
13b43665c4a6
145b58ab0a0b
1531d1882971
hex1bf86d27a3

120132020131 has 4 divisors (see below), whose sum is σ = 121481818200. Its totient is φ = 118782222064.

The previous prime is 120132020101. The next prime is 120132020143. The reversal of 120132020131 is 131020231021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120132020131 - 27 = 120132020003 is a prime.

It is a super-2 number, since 2×1201320201312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120132020101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 674898901 + ... + 674899078.

It is an arithmetic number, because the mean of its divisors is an integer number (30370454550).

Almost surely, 2120132020131 is an apocalyptic number.

120132020131 is a deficient number, since it is larger than the sum of its proper divisors (1349798069).

120132020131 is an equidigital number, since it uses as much as digits as its factorization.

120132020131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1349798068.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 120132020131 its reverse (131020231021), we get a palindrome (251152251152).

The spelling of 120132020131 in words is "one hundred twenty billion, one hundred thirty-two million, twenty thousand, one hundred thirty-one".

Divisors: 1 89 1349797979 120132020131