Search a number
-
+
12013301033 = 71169201423
BaseRepresentation
bin10110011000000110…
…00110110100101001
31011000020010220221022
423030003012310221
5144100401113113
65304022422225
7603462242156
oct131403066451
934006126838
1012013301033
115105216968
1223b3291975
131195b40a66
1481d6c122d
154a49eb908
hex2cc0c6d29

12013301033 has 4 divisors (see below), whose sum is σ = 12182502528. Its totient is φ = 11844099540.

The previous prime is 12013301017. The next prime is 12013301089. The reversal of 12013301033 is 33010331021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33010331021 = 152992157679.

It is a cyclic number.

It is not a de Polignac number, because 12013301033 - 24 = 12013301017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013304033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84600641 + ... + 84600782.

It is an arithmetic number, because the mean of its divisors is an integer number (3045625632).

Almost surely, 212013301033 is an apocalyptic number.

It is an amenable number.

12013301033 is a deficient number, since it is larger than the sum of its proper divisors (169201495).

12013301033 is an equidigital number, since it uses as much as digits as its factorization.

12013301033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 169201494.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 12013301033 its reverse (33010331021), we get a palindrome (45023632054).

The spelling of 12013301033 in words is "twelve billion, thirteen million, three hundred one thousand, thirty-three".

Divisors: 1 71 169201423 12013301033