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120133051 = 294142519
BaseRepresentation
bin1110010100100…
…01010110111011
322101001101120021
413022101112323
5221223224201
615530511311
72656054063
oct712212673
9271041507
10120133051
11618a2815
1234295537
131bb7265c
1411d523a3
15a82eea1
hex72915bb

120133051 has 4 divisors (see below), whose sum is σ = 124275600. Its totient is φ = 115990504.

The previous prime is 120133049. The next prime is 120133087. The reversal of 120133051 is 150331021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150331021 = 197912159.

It is a cyclic number.

It is not a de Polignac number, because 120133051 - 21 = 120133049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120133021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2071231 + ... + 2071288.

It is an arithmetic number, because the mean of its divisors is an integer number (31068900).

Almost surely, 2120133051 is an apocalyptic number.

120133051 is a deficient number, since it is larger than the sum of its proper divisors (4142549).

120133051 is an equidigital number, since it uses as much as digits as its factorization.

120133051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4142548.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 120133051 is about 10960.5223871857. The cubic root of 120133051 is about 493.4246430796.

Adding to 120133051 its reverse (150331021), we get a palindrome (270464072).

The spelling of 120133051 in words is "one hundred twenty million, one hundred thirty-three thousand, fifty-one".

Divisors: 1 29 4142519 120133051