1201333314241 has 4 divisors (see below), whose sum is σ = 1201546284484. Its totient is φ = 1201120344000.

The previous prime is 1201333314229. The next prime is 1201333314323. The reversal of 1201333314241 is 1424133331021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 960125619600 + 241207694641 = 979860^2 + 491129^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201333314241 - 2²⁵ = 1201299759809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201333314541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106476660 + ... + 106487941.

It is an arithmetic number, because the mean of its divisors is an integer number (300386571121).

Almost surely, 2^{1201333314241} is an apocalyptic number.

It is an amenable number.

1201333314241 is a deficient number, since it is larger than the sum of its proper divisors (212970243).

1201333314241 is an equidigital number, since it uses as much as digits as its factorization.

1201333314241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212970242.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1201333314241 its reverse (1424133331021), we get a palindrome (2625466645262).

The spelling of 1201333314241 in words is "one trillion, two hundred one billion, three hundred thirty-three million, three hundred fourteen thousand, two hundred forty-one".