Base | Representation |
---|---|
bin | 10110011000000110… |
… | …10000101000011011 |
3 | 1011000020012222001101 |
4 | 23030003100220123 |
5 | 144100403404321 |
6 | 5304023332231 |
7 | 603462500254 |
oct | 131403205033 |
9 | 34006188041 |
10 | 12013341211 |
11 | 5105244073 |
12 | 23b32b1077 |
13 | 1195b56131 |
14 | 81d6d1b2b |
15 | 4a4a08791 |
hex | 2cc0d0a1b |
12013341211 has 4 divisors (see below), whose sum is σ = 12013835512. Its totient is φ = 12012846912.
The previous prime is 12013341191. The next prime is 12013341293. The reversal of 12013341211 is 11214331021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11214331021 = 70183 ⋅159787.
It is a cyclic number.
It is not a de Polignac number, because 12013341211 - 213 = 12013333019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013341311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208701 + ... + 259966.
It is an arithmetic number, because the mean of its divisors is an integer number (3003458878).
Almost surely, 212013341211 is an apocalyptic number.
12013341211 is a deficient number, since it is larger than the sum of its proper divisors (494301).
12013341211 is an equidigital number, since it uses as much as digits as its factorization.
12013341211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 494300.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12013341211 its reverse (11214331021), we get a palindrome (23227672232).
The spelling of 12013341211 in words is "twelve billion, thirteen million, three hundred forty-one thousand, two hundred eleven".
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