Search a number
-
+
12013405401 = 34004468467
BaseRepresentation
bin10110011000000111…
…00000010011011001
31011000020100020002210
423030003200103121
5144100412433101
65304024545333
7603463155354
oct131403402331
934006306083
1012013405401
115105288318
1223b3322249
131195b7940a
1481d70b29b
154a4a1c7d6
hex2cc0e04d9

12013405401 has 4 divisors (see below), whose sum is σ = 16017873872. Its totient is φ = 8008936932.

The previous prime is 12013405363. The next prime is 12013405409. The reversal of 12013405401 is 10450431021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10450431021 = 33483477007.

It is not a de Polignac number, because 12013405401 - 227 = 11879187673 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013405409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002234231 + ... + 2002234236.

It is an arithmetic number, because the mean of its divisors is an integer number (4004468468).

Almost surely, 212013405401 is an apocalyptic number.

It is an amenable number.

12013405401 is a deficient number, since it is larger than the sum of its proper divisors (4004468471).

12013405401 is an equidigital number, since it uses as much as digits as its factorization.

12013405401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4004468470.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 12013405401 its reverse (10450431021), we get a palindrome (22463836422).

The spelling of 12013405401 in words is "twelve billion, thirteen million, four hundred five thousand, four hundred one".

Divisors: 1 3 4004468467 12013405401