Base | Representation |
---|---|
bin | 110111111100010101… |
… | …0101010101011111011 |
3 | 102111002111011202000002 |
4 | 1233320222222223323 |
5 | 3432014312121301 |
6 | 131104552303215 |
7 | 11452040405603 |
oct | 1577052525373 |
9 | 374074152002 |
10 | 120136051451 |
11 | 46a4973a639 |
12 | 1b3493a1b0b |
13 | b4374413a0 |
14 | 5b5943dc03 |
15 | 31d1dcc16b |
hex | 1bf8aaaafb |
120136051451 has 4 divisors (see below), whose sum is σ = 129377286192. Its totient is φ = 110894816712.
The previous prime is 120136051429. The next prime is 120136051459. The reversal of 120136051451 is 154150631021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120136051451 - 214 = 120136035067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120136051459) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4620617351 + ... + 4620617376.
It is an arithmetic number, because the mean of its divisors is an integer number (32344321548).
Almost surely, 2120136051451 is an apocalyptic number.
120136051451 is a deficient number, since it is larger than the sum of its proper divisors (9241234741).
120136051451 is an equidigital number, since it uses as much as digits as its factorization.
120136051451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9241234740.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 120136051451 its reverse (154150631021), we get a palindrome (274286682472).
The spelling of 120136051451 in words is "one hundred twenty billion, one hundred thirty-six million, fifty-one thousand, four hundred fifty-one".
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