12013633531553 has 4 divisors (see below), whose sum is σ = 12013641035568. Its totient is φ = 12013626027540.

The previous prime is 12013633531541. The next prime is 12013633531561. The reversal of 12013633531553 is 35513533631021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12013633531553 - 2⁶ = 12013633531489 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12013633531553.

It is not an unprimeable number, because it can be changed into a prime (12013633531253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 278951 + ... + 4909692.

It is an arithmetic number, because the mean of its divisors is an integer number (3003410258892).

Almost surely, 2^{12013633531553} is an apocalyptic number.

It is an amenable number.

12013633531553 is a deficient number, since it is larger than the sum of its proper divisors (7504015).

12013633531553 is an equidigital number, since it uses as much as digits as its factorization.

12013633531553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7504014.

The product of its (nonzero) digits is 364500, while the sum is 41.

The spelling of 12013633531553 in words is "twelve trillion, thirteen billion, six hundred thirty-three million, five hundred thirty-one thousand, five hundred fifty-three".