12014012552035 has 16 divisors (see below), whose sum is σ = 15886865975904. Its totient is φ = 8665563255552.

The previous prime is 12014012552029. The next prime is 12014012552089. The reversal of 12014012552035 is 53025521041021.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12014012552035 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12014012551988 and 12014012552006.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2149194442 + ... + 2149200031.

It is an arithmetic number, because the mean of its divisors is an integer number (992929123494).

Almost surely, 2^{12014012552035} is an apocalyptic number.

12014012552035 is a deficient number, since it is larger than the sum of its proper divisors (3872853423869).

12014012552035 is a wasteful number, since it uses less digits than its factorization.

12014012552035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4298394534.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 12014012552035 its reverse (53025521041021), we get a palindrome (65039533593056).

The spelling of 12014012552035 in words is "twelve trillion, fourteen billion, twelve million, five hundred fifty-two thousand, thirty-five".