12014201002403 has 4 divisors (see below), whose sum is σ = 12014376406968. Its totient is φ = 12014025597840.

The previous prime is 12014201002387. The next prime is 12014201002451. The reversal of 12014201002403 is 30420010241021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12014201002403 - 2⁴ = 12014201002387 is a prime.

It is a super-2 number, since 2×12014201002403² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12014201002103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87599501 + ... + 87736542.

It is an arithmetic number, because the mean of its divisors is an integer number (3003594101742).

Almost surely, 2^{12014201002403} is an apocalyptic number.

12014201002403 is a deficient number, since it is larger than the sum of its proper divisors (175404565).

12014201002403 is an equidigital number, since it uses as much as digits as its factorization.

12014201002403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175404564.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 12014201002403 its reverse (30420010241021), we get a palindrome (42434211243424).

The spelling of 12014201002403 in words is "twelve trillion, fourteen billion, two hundred one million, two thousand, four hundred three".