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120142305253353 = 3241251662039561
BaseRepresentation
bin11011010100010011001111…
…011011010101011111101001
3120202101111021211012220210110
4123110103033123111133221
5111221402420121101403
61103304340232204533
734206665215654545
oct3324231733253751
9522344254186713
10120142305253353
113531007a237309
1211584472b39749
1352064a8782cb6
142194cc08d6a25
15dd529c935103
hex6d44cf6d57e9

120142305253353 has 16 divisors (see below), whose sum is σ = 161495282596032. Its totient is φ = 79444747200000.

The previous prime is 120142305253343. The next prime is 120142305253379. The reversal of 120142305253353 is 353352503241021.

It is not a de Polignac number, because 120142305253353 - 213 = 120142305245161 is a prime.

It is not an unprimeable number, because it can be changed into a prime (120142305253343) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 330838308 + ... + 331201253.

It is an arithmetic number, because the mean of its divisors is an integer number (10093455162252).

Almost surely, 2120142305253353 is an apocalyptic number.

It is an amenable number.

120142305253353 is a deficient number, since it is larger than the sum of its proper divisors (41352977342679).

120142305253353 is a wasteful number, since it uses less digits than its factorization.

120142305253353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 662040056.

The product of its (nonzero) digits is 324000, while the sum is 39.

Adding to 120142305253353 its reverse (353352503241021), we get a palindrome (473494808494374).

The spelling of 120142305253353 in words is "one hundred twenty trillion, one hundred forty-two billion, three hundred five million, two hundred fifty-three thousand, three hundred fifty-three".

Divisors: 1 3 241 251 723 753 60491 181473 662039561 1986118683 159551534201 166171929811 478654602603 498515789433 40047435084451 120142305253353