12014342433 has 12 divisors (see below), whose sum is σ = 17363399508. Its totient is φ = 8005246560.

The previous prime is 12014342419. The next prime is 12014342441. The reversal of 12014342433 is 33424341021.

12014342433 is a `hidden beast` number, since 1 + 201 + 4 + 3 + 424 + 33 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 1108090944 + 10906251489 = 33288^2 + 104433^2 .

It is not a de Polignac number, because 12014342433 - 2⁹ = 12014341921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12014342397 and 12014342406.

It is not an unprimeable number, because it can be changed into a prime (12014342453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 341910 + ... + 375407.

It is an arithmetic number, because the mean of its divisors is an integer number (1446949959).

Almost surely, 2^12014342433 is an apocalyptic number.

It is an amenable number.

12014342433 is a deficient number, since it is larger than the sum of its proper divisors (5349057075).

12014342433 is a wasteful number, since it uses less digits than its factorization.

12014342433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 719184 (or 719181 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 12014342433 its reverse (33424341021), we get a palindrome (45438683454).

The spelling of 12014342433 in words is "twelve billion, fourteen million, three hundred forty-two thousand, four hundred thirty-three".