120144735133051 has 4 divisors (see below), whose sum is σ = 120255263869312. Its totient is φ = 120034206396792.

The previous prime is 120144735132893. The next prime is 120144735133061. The reversal of 120144735133051 is 150331537441021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120144735133051 - 2²³ = 120144726744443 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120144735132995 and 120144735133013.

It is not an unprimeable number, because it can be changed into a prime (120144735133061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55264366500 + ... + 55264368673.

It is an arithmetic number, because the mean of its divisors is an integer number (30063815967328).

Almost surely, 2^{120144735133051} is an apocalyptic number.

120144735133051 is a deficient number, since it is larger than the sum of its proper divisors (110528736261).

120144735133051 is a wasteful number, since it uses less digits than its factorization.

120144735133051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110528736260.

The product of its (nonzero) digits is 151200, while the sum is 40.

The spelling of 120144735133051 in words is "one hundred twenty trillion, one hundred forty-four billion, seven hundred thirty-five million, one hundred thirty-three thousand, fifty-one".