12014554771561 has 4 divisors (see below), whose sum is σ = 12019073222800. Its totient is φ = 12010036320324.

The previous prime is 12014554771553. The next prime is 12014554771631. The reversal of 12014554771561 is 16517745541021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12014554771561 - 2³ = 12014554771553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12014554751561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2259221631 + ... + 2259226948.

It is an arithmetic number, because the mean of its divisors is an integer number (3004768305700).

Almost surely, 2^{12014554771561} is an apocalyptic number.

It is an amenable number.

12014554771561 is a deficient number, since it is larger than the sum of its proper divisors (4518451239).

12014554771561 is an equidigital number, since it uses as much as digits as its factorization.

12014554771561 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4518451238.

The product of its (nonzero) digits is 1176000, while the sum is 49.

The spelling of 12014554771561 in words is "twelve trillion, fourteen billion, five hundred fifty-four million, seven hundred seventy-one thousand, five hundred sixty-one".