Base | Representation |
---|---|
bin | 110111111100110000… |
… | …1110101010000000001 |
3 | 102111010111101110000201 |
4 | 1233321201311100001 |
5 | 3432032012401031 |
6 | 131110230245201 |
7 | 11452304335525 |
oct | 1577141652001 |
9 | 374114343021 |
10 | 120150512641 |
11 | 46a56917535 |
12 | 1b3521b6801 |
13 | b43a4356c3 |
14 | 5b5b325d85 |
15 | 31d32d6d61 |
hex | 1bf9875401 |
120150512641 has 4 divisors (see below), whose sum is σ = 120153750192. Its totient is φ = 120147275092.
The previous prime is 120150512633. The next prime is 120150512777. The reversal of 120150512641 is 146215051021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 120150512641 - 23 = 120150512633 is a prime.
It is a super-2 number, since 2×1201505126412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120150912641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1562455 + ... + 1637548.
It is an arithmetic number, because the mean of its divisors is an integer number (30038437548).
Almost surely, 2120150512641 is an apocalyptic number.
It is an amenable number.
120150512641 is a deficient number, since it is larger than the sum of its proper divisors (3237551).
120150512641 is an equidigital number, since it uses as much as digits as its factorization.
120150512641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3237550.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 120150512641 its reverse (146215051021), we get a palindrome (266365563662).
The spelling of 120150512641 in words is "one hundred twenty billion, one hundred fifty million, five hundred twelve thousand, six hundred forty-one".
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