12015247033147 has 4 divisors (see below), whose sum is σ = 12030099008040. Its totient is φ = 12000395058256.

The previous prime is 12015247033123. The next prime is 12015247033189. The reversal of 12015247033147 is 74133074251021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12015247033147 is a prime.

It is a super-2 number, since 2×12015247033147² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12015247033247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7425986233 + ... + 7425987850.

It is an arithmetic number, because the mean of its divisors is an integer number (3007524752010).

Almost surely, 2^{12015247033147} is an apocalyptic number.

12015247033147 is a deficient number, since it is larger than the sum of its proper divisors (14851974893).

12015247033147 is an equidigital number, since it uses as much as digits as its factorization.

12015247033147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14851974892.

The product of its (nonzero) digits is 141120, while the sum is 40.

The spelling of 12015247033147 in words is "twelve trillion, fifteen billion, two hundred forty-seven million, thirty-three thousand, one hundred forty-seven".