1201789965313 has 4 divisors (see below), whose sum is σ = 1373474246080. Its totient is φ = 1030105684548.

The previous prime is 1201789965263. The next prime is 1201789965319. The reversal of 1201789965313 is 3135699871021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201789965313 - 2²¹ = 1201787868161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201789965319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85842140373 + ... + 85842140386.

It is an arithmetic number, because the mean of its divisors is an integer number (343368561520).

Almost surely, 2^{1201789965313} is an apocalyptic number.

It is an amenable number.

1201789965313 is a deficient number, since it is larger than the sum of its proper divisors (171684280767).

1201789965313 is an equidigital number, since it uses as much as digits as its factorization.

1201789965313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171684280766.

The product of its (nonzero) digits is 2449440, while the sum is 55.

The spelling of 1201789965313 in words is "one trillion, two hundred one billion, seven hundred eighty-nine million, nine hundred sixty-five thousand, three hundred thirteen".