Base | Representation |
---|---|
bin | 10110011000111010… |
… | …00110011111001011 |
3 | 1011000200222010111101 |
4 | 23030131012133023 |
5 | 144104122143103 |
6 | 5304424442231 |
7 | 603604203142 |
oct | 131435063713 |
9 | 34020863441 |
10 | 12020115403 |
11 | 510905067a |
12 | 23b5619377 |
13 | 119738862a |
14 | 820576759 |
15 | 4a53e5a1d |
hex | 2cc7467cb |
12020115403 has 4 divisors (see below), whose sum is σ = 12048667168. Its totient is φ = 11991563640.
The previous prime is 12020115391. The next prime is 12020115409. The reversal of 12020115403 is 30451102021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30451102021 = 223 ⋅136552027.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12020115403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12020115409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14275251 + ... + 14276092.
It is an arithmetic number, because the mean of its divisors is an integer number (3012166792).
Almost surely, 212020115403 is an apocalyptic number.
12020115403 is a deficient number, since it is larger than the sum of its proper divisors (28551765).
12020115403 is an equidigital number, since it uses as much as digits as its factorization.
12020115403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28551764.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 12020115403 its reverse (30451102021), we get a palindrome (42471217424).
The spelling of 12020115403 in words is "twelve billion, twenty million, one hundred fifteen thousand, four hundred three".
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