Base | Representation |
---|---|
bin | 1010111011101011000111… |
… | …0001110111010101000011 |
3 | 1120120010111110020112000211 |
4 | 2232322301301313111003 |
5 | 3033420034042224443 |
6 | 41322014453454551 |
7 | 2350303160545363 |
oct | 256726161672503 |
9 | 46503443215024 |
10 | 12020301133123 |
11 | 3914865691678 |
12 | 1421746641457 |
13 | 6926815a0caa |
14 | 2d7addc909a3 |
15 | 15ca2032119d |
hex | aeeb1c77543 |
12020301133123 has 16 divisors (see below), whose sum is σ = 12149777754400. Its totient is φ = 11891188592640.
The previous prime is 12020301133081. The next prime is 12020301133187. The reversal of 12020301133123 is 32133110302021.
It is a cyclic number.
It is not a de Polignac number, because 12020301133123 - 229 = 12019764262211 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12020301133094 and 12020301133103.
It is not an unprimeable number, because it can be changed into a prime (12020301139123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 179558968 + ... + 179625898.
It is an arithmetic number, because the mean of its divisors is an integer number (759361109650).
Almost surely, 212020301133123 is an apocalyptic number.
12020301133123 is a deficient number, since it is larger than the sum of its proper divisors (129476621277).
12020301133123 is a wasteful number, since it uses less digits than its factorization.
12020301133123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69622.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 12020301133123 its reverse (32133110302021), we get a palindrome (44153411435144).
The spelling of 12020301133123 in words is "twelve trillion, twenty billion, three hundred one million, one hundred thirty-three thousand, one hundred twenty-three".
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