12021001013433 has 4 divisors (see below), whose sum is σ = 16028001351248. Its totient is φ = 8014000675620.

The previous prime is 12021001013401. The next prime is 12021001013477. The reversal of 12021001013433 is 33431010012021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12021001013433 - 2⁵ = 12021001013401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12021001011433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003500168903 + ... + 2003500168908.

It is an arithmetic number, because the mean of its divisors is an integer number (4007000337812).

Almost surely, 2^{12021001013433} is an apocalyptic number.

It is an amenable number.

12021001013433 is a deficient number, since it is larger than the sum of its proper divisors (4007000337815).

12021001013433 is an equidigital number, since it uses as much as digits as its factorization.

12021001013433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4007000337814.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12021001013433 its reverse (33431010012021), we get a palindrome (45452011025454).

The spelling of 12021001013433 in words is "twelve trillion, twenty-one billion, one million, thirteen thousand, four hundred thirty-three".