Base | Representation |
---|---|
bin | 1010111011101110011101… |
… | …0111100100110000111001 |
3 | 1120120012211010000102000111 |
4 | 2232323213113210300321 |
5 | 3033423404223223001 |
6 | 41322244012104321 |
7 | 2350334355563602 |
oct | 256734727446071 |
9 | 46505733012014 |
10 | 12021200211001 |
11 | 3915187144143 |
12 | 14219577650a1 |
13 | 692795933a37 |
14 | 2d7b8744ada9 |
15 | 15ca74219851 |
hex | aeee75e4c39 |
12021200211001 has 4 divisors (see below), whose sum is σ = 12021213519504. Its totient is φ = 12021186902500.
The previous prime is 12021200210953. The next prime is 12021200211023. The reversal of 12021200211001 is 10011200212021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12021200211001 - 233 = 12012610276409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12021200212001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5192275 + ... + 7141576.
It is an arithmetic number, because the mean of its divisors is an integer number (3005303379876).
Almost surely, 212021200211001 is an apocalyptic number.
It is an amenable number.
12021200211001 is a deficient number, since it is larger than the sum of its proper divisors (13308503).
12021200211001 is an equidigital number, since it uses as much as digits as its factorization.
12021200211001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13308502.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 12021200211001 its reverse (10011200212021), we get a palindrome (22032400423022).
The spelling of 12021200211001 in words is "twelve trillion, twenty-one billion, two hundred million, two hundred eleven thousand, one".
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