Base | Representation |
---|---|
bin | 11011010101010111111010… |
… | …100001011001001011101011 |
3 | 120202122112121201020121100221 |
4 | 123111113322201121023223 |
5 | 111224104423413040033 |
6 | 1103402253153510511 |
7 | 34215215414655553 |
oct | 3325277241311353 |
9 | 522575551217327 |
10 | 120216042705643 |
11 | 35339379099625 |
12 | 11596811572437 |
13 | 521042a305281 |
14 | 21986b7a3c163 |
15 | dd716620912d |
hex | 6d55fa8592eb |
120216042705643 has 8 divisors (see below), whose sum is σ = 120731807713280. Its totient is φ = 119701322816040.
The previous prime is 120216042705587. The next prime is 120216042705653. The reversal of 120216042705643 is 346507240612021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 120216042705643 - 217 = 120216042574571 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 120216042705643.
It is not an unprimeable number, because it can be changed into a prime (120216042705653) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 261048963 + ... + 261509068.
It is an arithmetic number, because the mean of its divisors is an integer number (15091475964160).
Almost surely, 2120216042705643 is an apocalyptic number.
120216042705643 is a deficient number, since it is larger than the sum of its proper divisors (515765007637).
120216042705643 is an equidigital number, since it uses as much as digits as its factorization.
120216042705643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 522559017.
The product of its (nonzero) digits is 483840, while the sum is 43.
The spelling of 120216042705643 in words is "one hundred twenty trillion, two hundred sixteen billion, forty-two million, seven hundred five thousand, six hundred forty-three".
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