120221003000131 has 8 divisors (see below), whose sum is σ = 131150463208128. Its totient is φ = 109291589145000.

The previous prime is 120221003000117. The next prime is 120221003000159. The reversal of 120221003000131 is 131000300122021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120221003000131 - 2⁵ = 120221003000099 is a prime.

It is a super-2 number, since 2×120221003000131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120221003000171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6050145 + ... + 16644706.

It is an arithmetic number, because the mean of its divisors is an integer number (16393807901016).

Almost surely, 2^{120221003000131} is an apocalyptic number.

120221003000131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

120221003000131 is a deficient number, since it is larger than the sum of its proper divisors (10929460207997).

120221003000131 is a wasteful number, since it uses less digits than its factorization.

120221003000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23176433.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 120221003000131 its reverse (131000300122021), we get a palindrome (251221303122152).

The spelling of 120221003000131 in words is "one hundred twenty trillion, two hundred twenty-one billion, three million, one hundred thirty-one", and thus it is an aban number.