120221310310033 has 4 divisors (see below), whose sum is σ = 121868177574628. Its totient is φ = 118574443045440.

The previous prime is 120221310310021. The next prime is 120221310310037. The reversal of 120221310310033 is 330013013122021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 33124951463184 + 87096358846849 = 5755428^2 + 9332543^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120221310310033 is a prime.

It is a super-2 number, since 2×120221310310033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120221310309986 and 120221310310013.

It is not an unprimeable number, because it can be changed into a prime (120221310310037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 823433632188 + ... + 823433632333.

It is an arithmetic number, because the mean of its divisors is an integer number (30467044393657).

Almost surely, 2^{120221310310033} is an apocalyptic number.

It is an amenable number.

120221310310033 is a deficient number, since it is larger than the sum of its proper divisors (1646867264595).

120221310310033 is an equidigital number, since it uses as much as digits as its factorization.

120221310310033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1646867264594.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 120221310310033 its reverse (330013013122021), we get a palindrome (450234323432054).

The spelling of 120221310310033 in words is "one hundred twenty trillion, two hundred twenty-one billion, three hundred ten million, three hundred ten thousand, thirty-three".