12022313131 has 4 divisors (see below), whose sum is σ = 12028733752. Its totient is φ = 12015892512.

The previous prime is 12022313053. The next prime is 12022313153. The reversal of 12022313131 is 13131322021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131322021 = 7487 ⋅1753883.

It is a cyclic number.

It is not a de Polignac number, because 12022313131 - 2¹³ = 12022304939 is a prime.

It is a super-2 number, since 2×12022313131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12022313099 and 12022313108.

It is not an unprimeable number, because it can be changed into a prime (12022313731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3207501 + ... + 3211246.

It is an arithmetic number, because the mean of its divisors is an integer number (3007183438).

Almost surely, 2^12022313131 is an apocalyptic number.

12022313131 is a deficient number, since it is larger than the sum of its proper divisors (6420621).

12022313131 is an equidigital number, since it uses as much as digits as its factorization.

12022313131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6420620.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12022313131 its reverse (13131322021), we get a palindrome (25153635152).

The spelling of 12022313131 in words is "twelve billion, twenty-two million, three hundred thirteen thousand, one hundred thirty-one".